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Physics 7 Online
OpenStudy (anonymous):

a car slows down from -27.7m/s to -10.9 m/s while undergoing a displacement of -105m. what was its acceleration?

OpenStudy (abhisar):

Hello @avance1021 , Welcome to openStudy !

OpenStudy (abhisar):

use the equation of motion \(\sf v^2=u^2+2aS\) to find the acceleration (a) Take v=-10.9 u=-27.7 S=-105

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