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An official tennis court is a rectangle whose length is 6 feet more than twice the width. The perimeter of the court is 228 feet. Find the dimensions of the court. Can someone please help me? /:
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Perimeter for a rectangle is \(\sf P=2l +2w\), P=erimeter, w=width, l=length then the question says: length is 6 feet more than twice the width so l= 6+ 2w P= 228 ft substitute them in the formula \(\sf P=2l +2w\\228=2(6+2w)+2w\) now your turn, can you solve for 'w'
Isn't one equation L=2(w+6)?
@Data_LG2
sorry, late response. i'm not getting my notifications :/ why L=2(w+6)? the problem says length is 6 feet \(\sf more\) than \(\sf twice\ the\ width\)
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