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P(not a regular sprite) = 1 - P(a regular sprite) = 1 - 12/40 \[\large P(required)=(1-\frac{12}{40})^{5}=you\ can\ calculate\]
Yeah, thanks, I was missing that the exponent 5.
You're welcome :)
Man, I'm so sleepy, what time is it on yours
I'm not in your hemisphere, but understand your situation :)
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