Question

36r^24-25

Answer 1

(6r^12+5) (6r^12-5)

Answer 2

\[36r^{24}-25=6^2( r^{12})^2 - 5^2 = (6r^{12})^2-(5)^2\]

We knew that \(a^2-b^2 = (a+b)(a-b)\), and we can see that \(a=6r^{12}\) and \(b = 5\)

So \((6r^{12})^2-(5)^2=\boxed{(6r^{12}+5)(6r^{12}-5)}\)