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If p=1+2-3-4+5+6-7-8+...+1986, then p equals?
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you must use AP/GP
@ganeshie8 @zepdrix @iGreen
Did you know that 1+2+3+...10= (1+10)*(10/2)=55
So using that we get (1+1986)*(1986/2)=??
Sum = (\[Sum = \frac{ n (a + l)}{ 2 }\] Sum = (\[Sum = \frac{ 1986 (1 + 1986)}{ 2 }\] Sum = 1973091
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This is because we get pairs |dw:1416097786672:dw|
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