Question

Help Please
I have two questions :)

1.)WXYZ is a parallelogram. Name an angle congruent to 11 years ago

Answer 1

I believe the answer to your first question is D. angle WXY

Answer 2

thank you :)

Answer 3

2.) In parallelogram DEFG, DH=x+3, HF=3y, GH=4x-5, and HE=2y+3. Find the values of x and y. The diagram is not drawn to scale.

Answer 4

a.)x=6;y=3
b.)x=2;y=3
c.)x=3;y=2
d.)x=3;y=6

Answer 5

I forgot to explain why I chose answer choice D..
This is the definition of congruent: (of figures) identical in form; coinciding exactly when superimposed
And angle WXY is identical to angle WZY

Answer 6

I was thinking it was D too but I wasnt sure Thank You :)

Answer 7

For this you would simply plug in the values given (as the answers) and see which answer choice works out with this problem. So, which answer choice do you believe it is and I can show you whether or not it's right or not.

Answer 8

oh this is too confusing....

Answer 9

Okay, then just guess and I'll help you work it out.

Answer 10

okay um i think it may be a

Answer 11

Alright, so now we just have to plug in the values of x and y into the set of equations. Like this:
DH = 6 + 3
HF = 3(3)
GH = 4(6) - 5
HE = 2(3) + 3
Now we solve them...
DH = 9
HF = 9
GH = 19
HE = 9
For me to correctly answer this question I need to know if the lines segments that comes to a point in the center of the figure are identical? By that I mean do they appear to be the same size in the picture you were given?

Answer 12

yes the are identical, yes they are the same size

Answer 13

Okay, then answer choice A is wrong. Because they should all be the same value. Onto answer choice B..
Would you still like me to walk you through this or have you gotten the hang of it?

Answer 14

could you maybe keep helping me i don't get geometry very well :)

Answer 15

wait maybe i can get this

Answer 16

Okay, basically all we need to do know is solve the equation using the information given for answer choices B, C, and D. Wait, you don't need anymore help? Well, if you do just tag me by doing @Timmyk14

Answer 17

Thank you for all your help :)

Answer 18

No problem :)