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OpenStudy (anonymous):
calculate the molarity of0.0323 of moles of glucose c6h12o6 in 76.2ml of solution
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OpenStudy (anonymous):
well 0.0323 moles of glucose in 1 litre makes 0.0323M, if you want that in 76.2ml, you divide 0.0323 by 0.0762, giving a 0.424 molar solution
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