Question

circle area question

Answer 1

Can anyone help me?

Answer 2

\[A = (\theta /360)*\pi*r^2\]
\[16* \pi = (90 /360)*\pi*r^2\]
solve for r

Answer 3

I'm not sure what the radius is...

Answer 4

\[16* \pi /(90 /360)*\pi = r^2\]
\[16 /(1 /4) = r^2\]
\[16 *(4) = r^2\]
\[64 = r^2\]
\[\sqrt{64} = r\]
\[8 = r\]

Answer 5

Oh okay that makes sense now. Thank you for breaking it down like that :)

Answer 6

anytime :)