Question

x=vt cosθ and y=- 1/2 gt^2+vt sinθ+h find the Cartesian equation of motion

Answer 1

solve for t

Answer 2

x/( vcos theta) = t

y = -1/2 g [ x/( vcos theta) ]^2 + v[x/( vcos theta) ] sin theta + h

Answer 3

y = -1/2 * g * x^2 / ( v^2 cos^2 theta) + x* tan(theta) + h

Answer 4

y = -g/[2v^2 cos^2 theta]*x^2 + tan(theta)* x + h

Answer 5

OK thankyou very much perl

Answer 6

this agrees with wikipedia
http://en.wikipedia.org/wiki/Trajectory_of_a_projectile#Conditions_at_an_arbitrary_distance_x