Question

A 2 mi. cab ride costs $ 5.25. A 5 mi. cab ride costs $10.50. which equation models the cost y of the cab ride for ride that is x miles?
a. y = 1.75x - 1.75
b. y = 1.75x + 1.75
c. y = -1.75x - 1.75
d. y = -1.75x + 1.75

Answer 1

@Starrhazel1234 please help will reward and fan

Answer 2

I say D @jimmiedeel

Answer 3

I think the trick here is to realize that this cost and mileage are forming two points on a line so while it's not flat rate per dollar there is a gradual increasing cost (this would also make sense as when you get a taxi there is usually a fee you pay just to get in and the mileage builds from there).

Answer 4

YOU A DAB

Answer 5

What I did to solve this is find the equation of the line using slope intercept form y is the cost of the ride which increases as you increase mileage or move along the X axis. My points are (2, 5.25) and (5,10.5) y=mx+b
m=y2-y1/x2-x1
m=(10.5-5.25)/(5-2)
m=5.25/3=1.75 or 7/4


y=7/4x+b enter one point for the values of x and y to find b
10.5=(1.75X5) + b
10.5=8.75 + b
b=1.75


The equation of the line is y=7/4x+1.75 (I also double checked using the second point)



Then all you have to do is enter the mileage 3.8 for the value of X and solve for y
y=(7/4 X 3.8) + 1.75
y=6.65+1.75
y=8.4 The cab ride for the 3.8mile trip is $8.4

Does this help @jimmiedeel

Answer 6

Do I get a medal @jimmiedeel ?

Answer 7

No b/c that was not the right answer or solution