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Mathematics 13 Online
OpenStudy (anonymous):

Help? x+3/x^2-x-12 How would you work that out?

OpenStudy (taylev105):

get 1 number and 1 x by its self

OpenStudy (anonymous):

asalmaualykum

OpenStudy (anonymous):

Hi abswag13 :)

OpenStudy (anonymous):

asalam kayfahaluk

OpenStudy (anonymous):

x+3/x2-x-12 x+3/x2-4x+3x-12 x+3/x(x-4)+3(x-4) x+3/(x-4)(x+3) 1/x-4

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