Question

@amberk123 @myininaya

Answer 1

@cookiimonster27 Instead of re-drawing it you can also right click and save the image then click the attach file button.

Answer 2

is it the same question hun

Answer 3

that one is on the outside of the sqrt right?

Answer 4

Whats the solution

Answer 5

\[\sqrt{3x-5}=\sqrt{4x-3-1}\]

Answer 6

I Think that you have to do the same to each side.

Answer 7

\[\sqrt{3x-5}=\sqrt{4x-4}\]

Answer 8

yes thats it @amberk123

Answer 9

\[\sqrt{3x-5}=\sqrt{4x-4}\]
see what happens if you square both sides

Answer 10

Are you sure the minus 1 on the right hand side is not outside the radical sign?

Answer 11

@aum yes im sure

Answer 12

oh wait your its its outside @aum

Answer 13

Aha! It is too simple if it is inside!

Answer 14

so then we have this:
\[\sqrt{3x-5}=\sqrt{4x-3}-1 \] ?

Answer 15

yes

Answer 16

still need to square both sides

Answer 17

what do you get when you square both sides?

Answer 18

how do i do it ?

Answer 19

\[(\sqrt{3x-5})^2=(\sqrt{4x-3}-1)^2 \]
this gives you?

Answer 20

for the right hand side please do not say (a-b)^2=a^2-b^2
because it doesn't
(a-b)^2=a^2-2ab+b^2

Answer 21

i dont know how to do it

Answer 22

sqrt(3 x-5)-sqrt(4 x-3) = -1

Answer 23

how ? @amberk123

Answer 24

okay i will show u

Answer 25

\[\sqrt{3x-5+1}=\sqrt{4x-3}\]
\[\sqrt{3x-5}-\sqrt{4x-3=-1}\]

Answer 26

Lets have cookie work for the solution a little.

Answer 27

first of all do you know what this equals cookie
\[(\sqrt{9})^2=\]?

Answer 28

the reason I'm asking is because this is going to go right back to how to answer
\[(\sqrt{3x-5})^2\]

Answer 29

she offline