Can someone help me calculate the relative extrema for the graph of these functions?
f(x) = 1/4(x+2)(x-1)^2
h(x) = 2x^3+5x^2-25x

I did the work to find the intercepts. The first one is x=(-1,-5/3) and the second on is x=(5/2,-5)

Question

Can someone help me calculate the relative extrema for the graph of these functions?
f(x) = 1/4(x+2)(x-1)^2
h(x) = 2x^3+5x^2-25x

I did the work to find the intercepts. The first one is  x=(-1,-5/3) and the second on is x=(5/2,-5)

anonymous · Answer

for the first one:

ria23 · Answer

I need to show my work, I wasn't sure if I use the quadratic formula for this though...

anonymous · Answer

sorry, i cant help you with that, i just used an online program to graph it

ria23 · Answer

That's alright. Thank yhu for trying though. c:

anonymous · Answer

yeah(: sorry i couldnt help you more tho :/