Question

Write an equation of the tangent function with period 3pi/8, phase shift -pi/5, vertical shift -2.

Answer 1

What have you tried? Where do you fail to understand the question?

Answer 2

I wasn't at school and missed the whole unit. Was given no notes, no textbook for the class. Just need help knowing what to do. Even an example similar to this one I could probably solve it.

Answer 3

If the tangent function is: y = tan(Bx + C) + D
then:
Period = pi / B
Phase Shift = -C / B
Vertical shift = D

Answer 4

You can find B, C and D from: "period 3pi/8, phase shift -pi/5, vertical shift -2"

Answer 5

That's not one of my choices though.
I got something different

Answer 6

http://formula.algebra.com/cgi-bin/plot-formula.mpl?expression=y+=+tan%28%288%2F3%29x+%2B+%288%2Api%29%2F15%29+-+2&x=0003

Answer 7

Just noticed my mistake:
period = pi / B = 3pi/8
divide both sides by pi:
1/B = 3/8
cross multiply: 8 = 3B
B = 8/3 (had the reciprocal before)

phase shift = - C/B = -pi/5
multiply both sides by -1:
C/B = pi/5
cross multiply:
5C = pi * B = pi * 8/3
divide by 5:
C = pi * 8/3 * 1/5 = 8pi/15

D = vertical shift = -2

Therefore, the tan function is tan(Bx + C) + D = tan(8/3*x + 8*pi/15) - 2