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hi can someone help in Algebra 2: Has to do with SOLVING SYSTEMS BY SUBSTITUTION.
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take the last equation and find z in terms of x 2x+2z = 4 2z = 4-2x z = 2-x
next substitute for z in the first and second equations to get 2 equations in x and y
oooooh okay
Thank you :3
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so first equation becomes -x - y - (2-x) = -8 -x - y - 2 + x = -8 -y-2 = -8 y = 6 thats a bit of luck - we have value of y already
I guess you can continue from here ?
yeah i can, thank you again ^.^
yw
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