Question

solve the system using the elimination method twice
7x - 4y = 10
6x + 3y = 8

Answer 1

write the first equation in terms of x
\[x= (4y +10)/7\]

plug it into the x of the second equation

\[6(4/7y + 10/7) + 3y = 8\]

solve that equation for y and you will get

\[y = -4/45\]

plug that into the second equation and solve it for x

\[6x + 3(-4/45) = 8\]

you get

\[x = 62/45 \]

your answers are

\[y = -4/45, x = 62/45\]

if you plug these into both the equations they work