Question

Find the derivative of the equation in the comments.

Answer 1

using chain rule and quotient rule you should get:

\[-\sin(\frac{1-e^{4x}}{1+e^{4x}}) * \frac{-4 e^{4x}(1+e^4x)- 4 e^{4x}(1-e^{4x})}{(1+e^{4x})^2}\]
simplify