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\[\log_{4}(\log_{2}16) \]
consider what is \[\log _{2}16\]
16=2^x?
yeah, what is the x
log(4)
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keep in mind the base is 4
because of 16?
x is 4 because 2^4=16
the outer most log
now that you know it is four the thing you have to do is evaluate this \[\log _{4}4\]
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what is 4=4^y
one sec let me catch up
so 2^log(4) becomes 2^4
i don't know what 4=4^y is
what power of four is equal to four
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1
\[\log _{4}(\log _{2}16)\] \[\log _{4}4\] \[1\]
so those are the steps to solve this problem
THANK YOU
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