Ok, so my problem asks me to consider the region bounded by y = x^2, y =1, and y-axis for x (greater than or equal to) 0. Find the volume of the solid by rotating the region about the line y=-9. I got to this answer: pi times the integral from 0 to 1 of x^4+18x^2, but when I compute it I get a wrong answer. I'm not sure where I went wrong?

Question

Ok, so my problem asks me to consider the region bounded by y = x^2, y =1, and y-axis for x > (greater than or equal to) 0. Find the volume of the solid by rotating the region about the line y=-9. I got to this answer: pi times the integral from 0 to 1 of x^4+18x^2, but when I compute it I get a wrong answer. I'm not sure where I went wrong?

anonymous · Answer

Region of interest and axis of revolution:
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