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Consider this system of linear equations: 22x − y = -23 (equation 1) 11x + 12y = 1 (equation 2) To find the value of x, you need to substitute in equation 2. The value of x is .
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so you would set it up as y=22x-23 @mayankdevnani
no
be careful with the sign
y=22x+23
oh ok
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good
then put this value of y in equation no.2
tell me what you get ??
2
i mean put the value of `y` in equation no.2
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-1
i don't understand !
\[\large \bf 11x+12(22x+23)=1\] solve for x ?
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