Question

please help!!!
f(1) = 2 and f(2) = 5, f(n) = f(1) + f(2) + f(n - 1), for n > 2.

f(5) = ______

Answer 1

Will give medal and fan!!

Answer 2

this is what i got
F(x) = f(x f(x f(x)))

F‘(x) = f‘(x f(x f(x))) * [f(x f(x)) + x {f‘(x f(x)) * [f(x) + x f‘(x)]}]

F '(1) = f‘(f(f(1))) * [f(f(1)) + {f‘(f(1)) * [f(1) + f‘(1)]}]

F '(1) = f‘(f(2)) * [f(2) + {f‘(2) * [f(1) + 1]}]

F '(1) = f‘(3) * [3 + {2 * [2 + 1]}]

F '(1) = 3 * [3 + {2 * [2 + 1]}]

F '(1) = 27

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Answer 3

sorry i dont like when that happens

Answer 4

F(5) = f(1) + f(2) + f(5-1)= 2 + 5 + f(4) =7 + f(4)

now find f(4):
f(4) = 2 + 5 + f(3)= 7 + f(3)

now find f(3):
f(3) = 2 + 5 + f(2) = 7 + 5= 12

now solve f(4):
f(4) = 7+ 12 =19

now solve f(5):
f(5) = 7 + 19 = 26

We hope this helps.


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Answer 5

thx thats what i was trying to say

Answer 6

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