Question

Eliminate the parameter.

x = 5t, y = t + 8

y= 5x + 8
y = x/5 + 8
y = 5x - 8
y = x/5 - 8

I choose the last one as my answer. Is that right?

Answer 1

@mathmath333 can you help?

Answer 2

yes thats right

Answer 3

ya thats correct good job SunShine201

Answer 4

Thank you. Do you think you could check one more?

Answer 5

go ahead and post it.

Answer 6

ya ill check it to

Answer 7

Eliminate the parameter.

x = t2 + 3, y = t2 - 2

y = x + 5, x ≥ 1

y = x2 - 5, x ≥ 1

y = x - 5, x ≥ 1

y = x2 + 5, x ≥ 1

Answer 8

I think it's C but I also think it could be A. Which is it?

Answer 9

How are you trying to solve it?

Answer 10

The method matters more than the answer.

Answer 11

hey SunShine201 check out this link i posted it helps my friend realy realy good

http://www.wolframalpha.com/input/?i=x+%3d+t%5e2+%2b+3%2c+y+%3d+t%5e2+-+2&incTime=true

Answer 12

I don't know why the sign didn't show up but it is suppose to be for each answer

Answer 13

ok

Answer 14

anyway i got this since x = 2t^2 + t^2,
then x = 3 t^2
So t = (1/3 x) ^0.5
So y = 2/3 x + (1/3 x) ^1.5

Answer 15

hope this helps you

Answer 16

Thanks!

Answer 17

np brb