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Mathematics 7 Online
OpenStudy (anonymous):

(tan^3 x-1)/(tanx-1)-sec^2x+1=0 find cotx

OpenStudy (anonymous):

\[\frac{ \tan^3x-1 }{ tanx-1 }-\sec^2+1=0\]

OpenStudy (anonymous):

find cotx

OpenStudy (noelgreco):

fIRST, YOU HAVE TO FACTOR THE DIFFERENCE OF CUBES IN THE NUMERATOR for the first term.

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