A cheetah is running at a speed of 65mph while a gazelle is running at 47mph. If the gazelle is 1mi ahead of the cheetah, how far must the cheetah run to catch the gazelle? Please include an expression.

Question

anonymous · Answer

How do you take a screen shot help please

perl · Answer

lets use algebra
let c(t), g(t) be distances of cheetah

c(t) = 65*t 
g(t) = 47*t + 1

anonymous · Answer

I aggree

perl · Answer

then solve c(t) = g(t)

perl · Answer

65t = 47t + 1 

18t = 1 

t = 1/18

anonymous · Answer

Yay! you saved mah life, thanks :)

perl · Answer

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perl · Answer

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