Question

Find the center, foci, and vertices of the hyperbola. Use a graphing utility to graph the hyperbola and its asymptotes.
16y2 − x2 + 2x + 128y + 175 = 0

Answer 1

\[16y^2 − x^2 + 2x + 128y + 175 = 0\] subtract \(175\) and get
\[16y^2+128y − x^2 + 2x =-1750\] then time to complete the square

Answer 2

damn

Answer 3

I got the center, I need help finding the foci and vertices.

Answer 4

\[16y^2+128y-x^2+2x=-175\]

Answer 5

did you get in in the form
\[\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\]?

Answer 6

Yeah I know the formula but I get sqrt 5=a and 2sqrt5=b. And it says its wrong