Find the center, foci, and vertices of the hyperbola. Use a graphing utility to graph the hyperbola and its asymptotes.
16y2 − x2 + 2x + 128y + 175 = 0

Question

Find the center, foci, and vertices of the hyperbola. Use a graphing utility to graph the hyperbola and its asymptotes.
16y2 − x2 + 2x + 128y + 175 = 0

anonymous · Answer

$$16y^2 − x^2 + 2x + 128y + 175 = 0$$ subtract $175$ and get 
$$16y^2+128y − x^2 + 2x =-1750$$ then time to complete the square

anonymous · Answer

damn

happykiddo · Answer

I got the center, I need help finding the foci and vertices.

anonymous · Answer

$$16y^2+128y-x^2+2x=-175$$

anonymous · Answer

did you get in in the form 
$$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1$$?

happykiddo · Answer

Yeah I know the formula but I get sqrt 5=a    and   2sqrt5=b. And it says its wrong