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OpenStudy (anonymous):

x+4=-9

OpenStudy (anonymous):

please help

OpenStudy (anonymous):

x=5 if you use http://www.wolframalpha.com type in any answer that u need help with and it will answer any problem

OpenStudy (anonymous):

thank you sooo much

OpenStudy (anonymous):

ur welcome

OpenStudy (anonymous):

can you help me with more its home work

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

just post them and i look them up

OpenStudy (anonymous):

14-x=21 x=

OpenStudy (anonymous):

x=-7

OpenStudy (anonymous):

can we do 3 more

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

welcome

OpenStudy (anonymous):

what grade r u in

OpenStudy (anonymous):

-5x=-35 x=

OpenStudy (anonymous):

and im in 8th

OpenStudy (anonymous):

im just checking my answers

OpenStudy (anonymous):

@skatergurl916

OpenStudy (anonymous):

oh ok im 11

OpenStudy (anonymous):

hold on lemme solve the problem

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

ok so a negative and a negative equals a posotive so it x=6

OpenStudy (anonymous):

oh ya i got it right

OpenStudy (anonymous):

ok 2 more

OpenStudy (anonymous):

ok thats good

OpenStudy (anonymous):

-2x+8=-16 x=

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

-2x + 8 = -16 ⇒ x=12

OpenStudy (anonymous):

12 is the answer

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

last one

OpenStudy (anonymous):

k

OpenStudy (anonymous):

3(x-2)+5x=18 x=

OpenStudy (anonymous):

i was a bit confused

OpenStudy (anonymous):

omg u saved the hardest one for last

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

lol ok imma gve it a shot is it 3

OpenStudy (anonymous):

cause its a test online

OpenStudy (anonymous):

is one of the answers 3

OpenStudy (anonymous):

let me check how much % did i get

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

omg there's 5 more

OpenStudy (anonymous):

wow

OpenStudy (anonymous):

lmao ok lets do this aha

OpenStudy (anonymous):

ikr lol

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

ill do it all together

OpenStudy (anonymous):

8x-9=3x+16 x= 1^4x-8+2^4x=19 x=

OpenStudy (anonymous):

Jenna buys 12 lb of meat. Some of the meat is chicken and costs $1.90/lb. The rest is beef, which costs $4.30/lb. She spends a total of $34.80. Which equation models this situation? Let c represent the number of pounds of chicken she buys a.(1.9 + 4.3)(12 – c) = 34.8 b.4.3c + 1.9(c + 14) = 34.8 c.4.3c + 1.9(12) = 34.8 d.1.9c + 4.3(12 − c) = 34.8

OpenStudy (anonymous):

ok for 1 i got 2 answers so x = -4/3 x = 4

OpenStudy (anonymous):

ur in 8th grade???

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

lol! ur older than me! XD

OpenStudy (anonymous):

how old r u

OpenStudy (anonymous):

im really small

OpenStudy (anonymous):

but i need help

OpenStudy (anonymous):

for number 2 i got X=27/17

OpenStudy (anonymous):

i really need help for the last one don't get it

OpenStudy (anonymous):

@skatergurl916

OpenStudy (anonymous):

ik im trynna figure it out

OpenStudy (anonymous):

i think its d

OpenStudy (anonymous):

thats what i got

OpenStudy (anonymous):

ok then ill pick it

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ummm 2 more

OpenStudy (anonymous):

4(3x-5)+6=_____ Choose exactly two answers that are correct. a.4x-14+8x b.12x-14 c.6x+2(3x-8) d.7(x-2)+6x

OpenStudy (anonymous):

@skatergurl916

OpenStudy (anonymous):

this is the last one

OpenStudy (anonymous):

ok hold on

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

its b

OpenStudy (anonymous):

i was thinking it was c and b

OpenStudy (anonymous):

just b

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

let me check the %

OpenStudy (anonymous):

awwwwwww

OpenStudy (anonymous):

what

OpenStudy (anonymous):

i got 60%

OpenStudy (anonymous):

dang it

OpenStudy (anonymous):

well its better than an f

OpenStudy (anonymous):

you need help with math i could help you(: @sk

OpenStudy (anonymous):

@skatergurl916

OpenStudy (anonymous):

oh no it was the other girl i was helping her

OpenStudy (anonymous):

@Tabby_012 can you help me

OpenStudy (anonymous):

but when i need it

OpenStudy (anonymous):

oh @skatergurl916

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

thanks for helping

OpenStudy (anonymous):

yes anytime(: @skatergurl916

OpenStudy (anonymous):

but i helped so and ok

OpenStudy (anonymous):

ur welcome

OpenStudy (anonymous):

bye

OpenStudy (anonymous):

bye

OpenStudy (anonymous):

okay(:

OpenStudy (anonymous):

ok lol

OpenStudy (anonymous):

haha okay

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