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The vertex of f(x) = 2(x-2)2 +10 is (-2, 10). True False
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I think true
It's true because, the x coordinate of the vertex is: \[\frac{ -b }{ 2a }=-\frac{ -8 }{ 2*2 }=2\] now, if you substitute x=2 into the equation of your parabola, you would get the y-coordinate of the vertex, which is:y=f(2)=10
Sorry the vertex is (2,10)
So your answer is false, sorry again!
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