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can some one show me step by step of how to simplify the square root of 18
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\[\sqrt{18} = \sqrt{9*2} = \sqrt{3*3*2} \] as 9 is square of 3 then square root of 9 is 3 so \[\sqrt{18} = 3\sqrt{2}\]
i still dont get how u got yo anwser
\(\large \bf { \sqrt{18}\qquad \begin{cases} 18\to 3\cdot 3\cdot 2\\ 18\to 3^2\cdot 2 \end{cases}\implies \sqrt{18}\implies \sqrt{3^2\cdot 2} \\ \quad \\ \sqrt[{\color{brown}{ 2}}]{3^{\color{brown}{ 2}}}\cdot \sqrt[{\color{brown}{ 2}}]{2}\implies 3\cdot \sqrt[{\color{brown}{ 2}}]{2}\implies 3\sqrt{2} }\) see it now?
which part?
the anwser
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@jdoe0001 explanation worked?
i got it
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