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Use synthetic substitution to evaluate the polynomial for the given value. P(x) = x3 + 2x2 − 5x + 6 for x = −9
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\(\large {P(x) = 1x^3 + 2x^2 - 5x + 6 \div x = -9\\ \begin{array}{rrrrrrrrl} -9&|&1&2&-5&6\\ &|&&-9&? \\\hline\\ &|&1&-7 \end{array}}\) notice...all you do is, "drop" the first coefficient, and multiply times the divisor and put the result below the next term, and add them up and so on
so x=7? @jdoe0001
@jdoe0001
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