Question

Two times the width of a certain rectangle exceeds its length by three inches, and eight times its length is twelve more than its perimeter. Find the width of the rectangle.
Answer

6 inches

9 inches

12 inches

3 inches

Answer 1

l = 2
w = 0

Answer 2

w cant be zero... it is the width of a rectangle...

Answer 3

Wait i made a mistake...

Answer 4

I got it.. wait

Answer 5

Let the Length be x and Breadth be y.

Then , 2y = x + 3

x - 2y = 3 ------ (1)

And

8x = 2(x + y) + 12
8x = 2x + 2y + 12
8x - 2x - 2y = 12
6x - 2y = 12 --- cancelling throughout by 2 we get
3x - y = 6 --------(2)

Solve the 2 equations (1) & (2)

Answer 6

Did you understand it?

Answer 7

translate the two sentences.

2w=L +3
and
8L=12+2L+2w

subtract both sides by 3 and you get L=2w-3
plug this into your second equation

8(2w-3)= 12+2(2w-3)+2w
and you can solve for w, which is the width.

Answer 8

w = 3

Answer 9

the final answer is 3?

Answer 10

correct

Answer 11

Thnx!