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what is the equation of the axis of symmetry for the function shown below y+5=-2(x-2)^2
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|dw:1416476868967:dw|
if you draw the graph, the symmetry is at x=2
x = -b/2a from the general standard form equation y = ax2+bx + c
so convert your equation to standard form and solve using above.
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x= h in the general vertex form equation y = (x-h)2 + k so modify your equation to THAT form and you have h
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