Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

what is the equation of the axis of symmetry for the function shown below y+5=-2(x-2)^2

OpenStudy (anonymous):

OpenStudy (anonymous):

|dw:1416476868967:dw|

OpenStudy (anonymous):

if you draw the graph, the symmetry is at x=2

OpenStudy (mrnood):

x = -b/2a from the general standard form equation y = ax2+bx + c

OpenStudy (mrnood):

so convert your equation to standard form and solve using above.

OpenStudy (mrnood):

x= h in the general vertex form equation y = (x-h)2 + k so modify your equation to THAT form and you have h

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!