Question

Ok so can some one just like give me the equation solved like all together. I will fan and medal. I wrote it wrong last time hers the correct equation

Solve the system by substitution

-x-y-z=-8
-4x+4y+5z=7
2x+2z=4

Answer 1

do you know what mean by substitution ?

Answer 2

like a first step in case of 3rd equation factoriz out the 2 on both sides and divide both sides by 2

2x+2z=4
2(x+z)=4 /:2
x+z=2
x=2-z

in case of first equation

-x-y-z=-8 rewrite it

-(x+y+z)= -(8) and divide both sides by -1 and will get

x+y+z=8 so but you know that x=2-z so this you can substituting in place of x inside equation x+y+z =8 so will get

2-z+y+z=8
2+y=8
y=8-2
y=6

so you know y=6 now just you need substituting this y=6 in second equation and will get -4x+4*(6) +5z=7

-4x +24 +5z=7

-4x +5z= - 17

so but you know that x=2-z than now just you need substituting this x=2-z in place of x inside equation -4x+5z=-17
-4(2-z)+5z=-17
-8+4z+5z=-17
-8+9z=-17
9z=-9
z=-1

but you know that x=2-z so x=2-(-1) so x=2+1 so x=3

than result

x=3
y=6
z=-1

hope so much that this will help you understanding all right easy

good luck

bye

Answer 3

Thank you for your help.

Answer 4

np

was my pleasure

bye