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\[\frac{ 4 }{ 5 }x ^{3}(\frac{ -7 }{ 2 }x ^{2})\]
hmmm actuall is a 3
\(\bf \cfrac{ 4 }{ 5 }x ^{3}\left(\cfrac{ -7 }{ 2 }x ^{2}\right)\implies \cfrac{ 4x^3}{ 5 }\cdot \cfrac{ -7 x ^{2}}{ 2 }\implies \cfrac{4x^3\cdot -7 x ^{2}}{ 5\cdot 2 }\implies \cfrac{4\cdot -7\cdot x^3\cdot x ^{2}}{ 5\cdot 2 }\)
I thought you multiplied the feactions and then addded the exponents?
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