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Mathematics 9 Online
OpenStudy (anonymous):

@myininaya

OpenStudy (anonymous):

@sourwing can you please explain?

OpenStudy (anonymous):

implicit diffrentiation

OpenStudy (anonymous):

cacn you write the steps? im so confused

OpenStudy (anonymous):

so d/dt (y) = dy/dt yes? what is d/dt (x^3) ?

OpenStudy (anonymous):

and what is d/dt (2x)

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

d/dt (x^3) = 3x^2 (dx/dt) , using the chain rule

OpenStudy (anonymous):

and d/d(2x) = 2 (dx/dt) so you have: dy/dt = 3x^2 (dx/dt) + 2 (dx/dt) you're given x = 2 and dx/dt = 5. Plug and chug

OpenStudy (anonymous):

sorry oopenstudy logged me out

OpenStudy (anonymous):

70? @sourwing

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you!

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