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what is the value of 6 x 8-4[7+(8-3)]
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0
how did you get 0?
8-3=5
+7=12
*4=48
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6x8=48
48-48=0
thanks!! can you help me with a few more?
sure np
combine like terms to simplify the expression. 9+3+17xy^2+8y^3+10x-13xy^2-9x-6y^3
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hallo?
okay there
ok let me get some paper lol
alright :)
1x+2y-4xy^23
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oh god sorry it is 8xy+6y+x+12
im going to msg u
ok sounds good
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