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Write the expression tan(sin^-1)x) as an algebraic expression in x (without trig or inverse trig functions).
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|dw:1416538624526:dw|
there is an angle whose sine is \(x\) to find the tangent of that angle, you need the third side, which you find via pythagoras as \[\sqrt{1-x^2}\]
then tangent is "opposite over adjacent"
tan(2arcsinx) is the equation sorry.
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