PLEASE ANSWER THE FIRST PART IF YOU CAN ):!Suppose you play a game of chance where you roll a pair of dice. You pay a nonrefundable $2 to play the game. If the number of dots on both dice is even, you win $6. Otherwise you win nothing. 1) what is the probability of winning. 2) create a probability distribution table for X where is X is the random variable.
the dice must both be even, or show a 2,4,or 6 this leaves only 3 options for each die ---> 3*3 = 9 possible winning combinations There are a total of 6*6=36 combinations probability = 9/36 = 1/4
thank you soo much!
yw i wouldnt play this game .... on avg you will lose 50 cents per game :)
lmaooo haha yea i dont think anyone would XD
yet millions play the lottery ...go figure haha
false hope is good sometimes xD
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