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Find an equation for the nth term of the arithmetic sequence. 14th term = -33 15th term = 9
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a+13d=-33 a+14d=9 where a is first term and d is common difference. Now, for nth term use a+(n-1)d. Put values of a and d from the above two equations.
d = -24 ... ???
I'm not quite following
d=9-(-33)=42
ohh gotcha!
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so d = 42 so the 14th term is -33 -33 = a + (14 -1)42 -33 = a + (13)42 -33 = a + 546 -33 - 546 = a -579 check: 15th term (n = 15) -579+ (15 - 1)42 = ? -579 + (14)42 = ? -579 + (588) = ? =9 so a = -579 d = 42 equation is -579 + 42(n-1)
@BPDlkeme234 wow! I really appreciate that!
Elementary! LOL
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