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How do I turn X^2 - 7 = 4x + 5 into completing the square problem?
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\[(x-2)^{2}=8\]
How did you get the eight?
first you have to move 4x on left side
\[x^2 -4x = 12\] \[x^2 -4x + (\frac{4}{2})^2 = 12 + (\frac{4}{2})^2\]
|dw:1416543087539:dw|
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then move 7 on right side
|dw:1416543387742:dw|
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