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OpenStudy (clamin):
HELP!! 5k^2+39k+28 factor
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OpenStudy (anonymous):
(5k )( k )
OpenStudy (anonymous):
now you are looking for 2 number if you multiply them and when you add them gives the one in the mid
OpenStudy (anonymous):
4*7=28 2*14=28
OpenStudy (anonymous):
(5k +4 )(k +7 )
OpenStudy (anonymous):
5k*k=5k^2 5k*7=35k 4*k=4k 4*7=28 adding 5k^2+39k+28
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