The interior angles of a convex polygon are in AP. If the largest angle is 140, and the smallest is 100, then the number of sides of the polygon is? 6, 8, 10, 11 or 12
@ikram002p
@ganeshie8
@jim_thompson5910
@Compassionate
\[100 + (n-1)d = 140\] \[(n-1)d = 40\]
not sure
i might confsed u xD i remove my comments and read carfully what ganesh wrote
so its 11?
Also the interior angles must add up to : \(180(n-2)\)
So you have two equations basically : \[(n-1)d = 40\tag{1}\] \[\frac{n}{2}\left[2\times 100 + (n-1)d\right] = 180(n-2)\tag{2}\]
you can solve them http://www.wolframalpha.com/input/?i=solve+%28n-1%29d+%3D+40%2C%5Cfrac%7Bn%7D%7B2%7D%5Cleft%5B2%5Ctimes+100+%2B+%28n-1%29d%5Cright%5D+%3D+180%28n-2%29
wait is it 6 or 8
you have two equations and two unknowns, you can solve them right ?
ooooo its 6 right? sorry
yes let me knw if something doesnt make sense..
it makes sense i gott another one
we have used "nth term" and the "partial sum" formulas of AP
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