Question

how many ml of a 50 acid solution and how many ML of 20% acid solution must be mixed to produce 36ml of a 30% acid solution

Answer 1

Do you have any ideas about how we start with this question?

Answer 2

none at all

Answer 3

OK.

Suppose that the volume of the 50% acid solution is \(x\) and the volume of 20% acid solution is \(y\).

When we mix these two solutions, we get a 36 ml solution. Therefore, the sum of volumes of those two solutions must be 36. In math lingo, it's \(x+y = 36.\) That's our first equation.

Answer 4

okay

Answer 5

so you substitute the other vlues for x and y?

Answer 6

Now, 50% of the volume of the 50% acid solution is pure acid. And 20% of the volume of the 20% acid solution is pure acid.

Also, when you mix those, you get 30% of 36 ml pure acid.

Answer 7

okay thank you i think i got it from this point.