OpenStudy (anonymous):

how many ml of a 50 acid solution and how many ML of 20% acid solution must be mixed to produce 36ml of a 30% acid solution

3 years ago
OpenStudy (owlfred):

3 years ago
OpenStudy (anonymous):

none at all

3 years ago
OpenStudy (owlfred):

OK. Suppose that the volume of the 50% acid solution is $$x$$ and the volume of 20% acid solution is $$y$$. When we mix these two solutions, we get a 36 ml solution. Therefore, the sum of volumes of those two solutions must be 36. In math lingo, it's $$x+y = 36.$$ That's our first equation.

3 years ago
OpenStudy (anonymous):

okay

3 years ago
OpenStudy (anonymous):

so you substitute the other vlues for x and y?

3 years ago
OpenStudy (owlfred):

Now, 50% of the volume of the 50% acid solution is pure acid. And 20% of the volume of the 20% acid solution is pure acid. Also, when you mix those, you get 30% of 36 ml pure acid.

3 years ago
OpenStudy (anonymous):

okay thank you i think i got it from this point.

3 years ago