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Mathematics 6 Online
OpenStudy (anonymous):

There are four cards: A B 1 2 What cards would you need to flip to test the following statement: If a card is even, the the other side will contain a vowel.

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

Dan, you chose to flip A and 2. Let's say on the other side of A is 3, and on the other side of 2 is E.

OpenStudy (anonymous):

Does the statement still hold?

OpenStudy (dan815):

Odd has a vowel, and 2 has a vowel thas okay it says Vowel if number is Even not Vowel only if number is even

OpenStudy (anonymous):

Next question. Is it possible that the statement is false?

OpenStudy (dan815):

if when we flip B, we saw an even then it can be false

OpenStudy (anonymous):

Yeah, that's the trick.

OpenStudy (anonymous):

Do you get it now?

OpenStudy (dan815):

:) REALLY??!

OpenStudy (dan815):

i dunno lol cuz i saw no point of confusion anywhere

OpenStudy (anonymous):

Well, you chose A and 2, but you had to chose B and 2

OpenStudy (dan815):

ok wait lemme think

OpenStudy (anonymous):

Both A and 1 are inconsequential, but for some reason you picked A.

OpenStudy (dan815):

oh i see okayy A can have odd or even yes

OpenStudy (dan815):

yeahh i see i took th statement/ Vowel iff even but its Vowe if even

OpenStudy (anonymous):

Even -> Vowel means Not Even OR Vowel. The contradiction would be Even AND Not Vowel

OpenStudy (dan815):

if even then vowel iff even then vowel different from if even then vowel if odd then vowel or not vowel

OpenStudy (dan815):

yee i see okay

OpenStudy (anonymous):

It's extremely simple, but easy to jump to the wrong conclusion.

OpenStudy (anonymous):

Most people will pick A and 2, just like you did.

OpenStudy (anonymous):

And some people will think you need to flip all four to be sure.

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