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find derivative
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\[f(x) = \frac{ 3x^2 +6x +5 }{ \sqrt{x} }\]
i am going to assume quotient rule
\[f(x) = \frac{ 3x^2 +6x +5 }{ \sqrt{x} }=( 3x^2 +6x +5)x^{-{1/2}}=3x^{3/2}+6x^{1/2}+5x^{-1/2}\]
now differentiate
okay, give me a few with these fractions
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\[3x ^{1/2}+3x ^{-1/2}-5/2^{-3/2}\]
@Zarkon
3*(3/2)=9/2
okay so \[\frac{ 9 }{ 2 }x ^{1/2} + 3x ^{-1/2} - \frac{ 5 }{ 2}x ^{-3/2}\]
yes
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can I simplify?
I wouldn't
Okay, let me try putting this in
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