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squared x+8=x-4 a. 8 b. -1 c. -4,4 d. no real number solution
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8 -4 so 4?
c is the answer?
D ithink
why?
?... \(x^2 -8 = x+4\) is that your question?..
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√x+8=x-4
Oh, \[\sqrt{x-8}=x+4\] Start by squaring both sides \[(\sqrt{x-8})^2 = (x+4)^2\]
A
X+8=X^2+16-8X
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X^2-9X+8=0
DELTA=81-32=49
so it would be a?
X1++9+7/2=8
When you square both sides, the square root goes away,leaving you with:\[(\sqrt{x-8})^2 = (x+4)^2\]\[x-8 = x^2 +8x+16\]
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,X2=9-7/2=1
IT'S A
@Jhannybean (X-4) NOT (X+4)
thanks guys can u help me with more?
Oop, typo.
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YEP
should i open a new question?
YEP
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