Mathematics
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OpenStudy (anonymous):
The volume of a child's model plane is 1200 cm^3
The volume of the full size plane is 4050 m^3
Find the scale of the model in the form 1:n
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jhonyy9 (jhonyy9):
will be
4050/1200 = 405/120 = 81/24 = 27/8 = 1/n
27/8 = 1/n cross multiplie
27n=8
n= 8/27
result this scale will be 1/(8/27)
hope is understandably
OpenStudy (anonymous):
but 4050 m3 should be changed to cm3 right?
OpenStudy (anonymous):
@jhonyy9
jhonyy9 (jhonyy9):
oh yes sorry i missed it
jhonyy9 (jhonyy9):
or invers 1200 cm^3 = ? m^3
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jhonyy9 (jhonyy9):
1 m^3 = ? cm^3
OpenStudy (anonymous):
=1,000,000 cm^3
OpenStudy (anonymous):
so 4050m^3 would be 4,050,000,000?
jhonyy9 (jhonyy9):
yes right but i think will be more easy without this so great numbers than you change 1200 cm^3 in m^3
how you think it ?
jhonyy9 (jhonyy9):
but you can rewrite this result using 4*10^9 (standard form)
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jhonyy9 (jhonyy9):
so 4050m^3 would be 4,050,000,000
OpenStudy (anonymous):
yes
jhonyy9 (jhonyy9):
so 4050m^3 would be 4,050,000,000 = 4*10^9
yes ?
jhonyy9 (jhonyy9):
or 1200 cm^3 = ? m^3
OpenStudy (anonymous):
1200 cm^3=0.0012 m^3
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jhonyy9 (jhonyy9):
rewrite it using power of 10
jhonyy9 (jhonyy9):
1200 = aproximatly 1*10^3
OpenStudy (anonymous):
1.2x10^-3
OpenStudy (anonymous):
n=4*10^9 / 10^3
jhonyy9 (jhonyy9):
yes 1,2*10^-3 but you can consider it 1*10^-3 = 10^-3
ok ?
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OpenStudy (anonymous):
okay
jhonyy9 (jhonyy9):
so than will result
1/n = 10^-3 / 4*10^9
n=?
jhonyy9 (jhonyy9):
so n= ?
OpenStudy (anonymous):
2.5*10^-13?
OpenStudy (anonymous):
umm
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OpenStudy (anonymous):
but the answer is supposed to be n=150
:/
jhonyy9 (jhonyy9):
yes but you need writing your answer in this 1/n form
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
OpenStudy (anonymous):
isnt it supposed to be related to that?
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jhonyy9 (jhonyy9):
so than us this 2,5 *10^-13
so than from 2,5/4 you will get 0,6
because 1/150 = 0,006 = 6*10^-3