Question

Find all solutions of the equation (tanx+1)(2sinx-1)=0 in the interval [0,2pi)

Answer 1

I think I can help

Answer 2

2 sinx + cosx = 0
let us divide by cosx ≠ 0:
2 sinx/cosx + cosx/cosx = 0 →
2 tanx + 1 = 0 →
2 tanx = - 1 →
tanx = -1/2 →
x₁ = -26°33'54"+180° = 153°26'05"
x₂ = 153°26'05" + 180° = 333°26'05" tht wht I got