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Find all solutions of the equation (tanx+1)(2sinx-1)=0 in the interval [0,2pi)
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2 sinx + cosx = 0 let us divide by cosx ≠ 0: 2 sinx/cosx + cosx/cosx = 0 → 2 tanx + 1 = 0 → 2 tanx = - 1 → tanx = -1/2 → x₁ = -26°33'54"+180° = 153°26'05" x₂ = 153°26'05" + 180° = 333°26'05" tht wht I got
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