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factor the trinomial 3x^2-17x-6
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twilight i go it!
3x^2-17x-6 -----> (3x ) ( x ) = 3x^2
(3x+1) (x-6)
times that stuff all together 3x*x= 3x^2 - 18x+1x-6 solve and get orignal
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thank you so much!
:D
\[3x^2-17x-6\]\[x^2 -17x -18\]\[(x-18)(x+1)\]\[\left(x-\frac{18}{3}\right)\left(x+\frac{1}{3}\right)\]Simplify whichever fractions can simplify, and then multiply the denominators of the fractions that do not simplify that easily. \[(x-6)(3x+1)\]
We divided our factored form by 3 because we initially multiplied it to the constant to make it easier to simplify.
thank you @Jhannybean !
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