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Mathematics
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13C9 Srry
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\[\binom{13}{6} = ~_{13}C_6 = \dfrac{13!}{6!(13-6)!} = \dfrac{13!}{6!(7!)} = \dfrac{13\cdot12\cdot11\cdot10\cdot9\cdot8}{6\cdot5\cdot4\cdot3\cdot2}=~\cdots~?\]
Well, you get the idea.
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