Question

13C9 Srry

Answer 1

\[\binom{13}{6} = ~_{13}C_6 = \dfrac{13!}{6!(13-6)!} = \dfrac{13!}{6!(7!)} = \dfrac{13\cdot12\cdot11\cdot10\cdot9\cdot8}{6\cdot5\cdot4\cdot3\cdot2}=~\cdots~?\]

Answer 2

Well, you get the idea.

Answer 3

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