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OpenStudy (anonymous):
find all the solutions for z =C z^4-3z^2+4=0
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OpenStudy (anonymous):
Just let \(u = z^2\) So then you would have \(u^2-3u+4=0\) Can you solve for u?
Directrix (directrix):
>> for z =C What does this mean? Do you mean that the solutions for z are to come from the set of complex numbers? Just wondering.
OpenStudy (anonymous):
I'm sure =C is just sad face.
OpenStudy (anonymous):
|dw:1416779906671:dw|
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