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Mathematics 11 Online
OpenStudy (anonymous):

find all the solutions for z =C z^4-3z^2+4=0

OpenStudy (anonymous):

Just let \(u = z^2\) So then you would have \(u^2-3u+4=0\) Can you solve for u?

Directrix (directrix):

>> for z =C What does this mean? Do you mean that the solutions for z are to come from the set of complex numbers? Just wondering.

OpenStudy (anonymous):

I'm sure =C is just sad face.

OpenStudy (anonymous):

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